Question

The perimeter of a rhombus is 112 cm and area is 238 m2 ,find its diagonals
.

Answer 1

A=pq

2

P=4a

a=p2+q2

2

There are 2 solutions forp

p=2P2P2+P4﹣256A2﹣2P4﹣256A2P2+P4﹣256A2

64A=2·1122·1122+1124﹣256·2382﹣2·1124﹣256·2382·1122+1124﹣256·2382

64·238≈8.60209

p=2P2P2﹣P4﹣256A2+2P4﹣256A2P2﹣P4﹣256A2

64A=2·1122·1122﹣1124﹣256·2382+2·1124﹣256·2382·1122﹣1124﹣256·2382

64·238≈55.33