Math, asked by priyanshu7903590883, 1 year ago

The perimeter of a rhombus is 146 cm and one of its diagonals is 48 cm, find the other diagonal and the area of the rhombus.

Answers

Answered by Debdipta
6
we know that,the diagonals of rhombus bisect each other at 90°.
the half of the diagonal =48×1/2=24cm
the each side=146/4=36.5cm
the haf of the other diagonal=√(36.5^2-24^2)=27.5cm
the length of the diagonal=27.5×2=55
Answered by Híɾo
439

 {\huge {\underline {\bf {\blue {Question}}}}}

The perimeter of a rhombus is 146 cm and one of its diagonals is 48 cm, find the other diagonal and the area of the rhombus.

 {\huge {\underline {\bf {\blue {Answer}}}}}

Given :-

  • The perimeter of a rhombus = 146 cm
  • One of its diagonal = 48 cm.

To Find :-

  • Other diagonal of rhombus
  • Area of the rhombus.

Solution :-

We know that, all sides of rhombus are equal.

 {\boxed {\sf {Perimeter~ of~ rhombus = 4 \times side}}}

 ~

Perimeter of rhombus = 146 cm

 ~

 {\sf {4 \times side = 146~ cm}}

 ~

 {\sf {Side = {\dfrac {146}{4}} ~ cm}}

 ~

 {\sf {Side = 36.5~ cm}}

 ~

Diagonals in a rhombus bisect each other at right angles. O is the midpoint of AC and BD. But BD = 55. therefore, OB = OD = 27.5 cm

In △AOB

∠AOB = 90°

By Pythagoras theorem,

 ~

 \implies  {\sf {{AB}^{2} = {AO}^{2} + {OB}^{2}}}

 ~

 \implies  {\sf {{36.5}^{2} = {AO}^{2} + {27.5}^{2}}}

 ~

 \implies  {\sf {{36.5}^{2} - {27.5}^{2} = {AO}^{2}}}

We know,

 {\boxed {\sf { (a + b) (a - b) = {a}^{2} - {b}^{2}}}}

 ~

 \implies  {\sf { (36.5 + 27.5) (36.5 - 27.5) = {AO}^{2}}}

 ~

 \implies  {\sf {64 \times 9 = {AO}^{2}}}

 ~

 \implies  {\sf { {AO}^{2} = 576}}

 ~

 \implies  {\sf {AO = 24 cm}}

 ~

 {\underline {\boxed {\sf { Length~ of~ diagonal~ AC = 24 + 24 = 48~ cm}}}}

Also,

 {\boxed {\sf { Area~ of~ Rhombus = {\dfrac {1}{2}} \times {d}_{1} \times {d}_{2} }}}

 ~

 \implies  {\sf { Area~ of~ Rhombus = {\dfrac {1}{2}} \times 48 \times 55 }}

 ~

 \implies  {\sf { Area~ of~ Rhombus = {\dfrac {1}{ {\cancel {2}}}} \times {\cancel {{48}}^{24}} \times 55 }}

 ~

 \implies  {\sf { Area~ of~ Rhombus = 24 \times 55}}

 ~

 {\underline {\boxed {\sf { Area~ of~ Rhombus = 1320~ {cm}^{2}}}}}

 {\underline {\sf {\purple {Hence,~ Length~ of~ other~ diagonal~ is~ 48~ cm}}}}

 {\underline {\sf {\purple {Area~ of~ Rhombus~ is~ 1320 {cm}^{2}}}}}

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