the perimeter of a rhombus is 20 cm and one of its diagonal is 6 cm long find the length of other diagonal
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HERE IS THE SOLUTION;
£ Given : Perimeter =20Cm.
length of one diagonal is 6 Cm.
Let AC be the first diagonal.
£ To find : Length of other diagonal.
£ Solution :
◆ We know that rhombus has 4 sides so, to get one side.
=> 24 = 4× Side.
=> Side = 24÷4 = 6Cm.
◆ We also know that diagonals of rhombus bisects each other at right angles and are equal.
So, In triangle AOD;
By Pythagoras Theorem;
AO= 1/2 AC
AO =1/2 × 6
AO=3Cm.
Also we know that side is 6Cm;
AD^2= DO ^2 + AO^2.
=> (6)^2= DO^2+ (3)^2
=> 36 = DO ^2 + 9
=> DO^2= 25
=>DO=5Cm.
◆ Since we know that BD is another diagonal &. DO = 1/2 BD.
=> BD = 2×DO
=> BD = 2×5
=> BD = 10 Cm.
◆◆ So the other diagonal is 10 Cm◆◆
HOPE IT HELPS
£ Given : Perimeter =20Cm.
length of one diagonal is 6 Cm.
Let AC be the first diagonal.
£ To find : Length of other diagonal.
£ Solution :
◆ We know that rhombus has 4 sides so, to get one side.
=> 24 = 4× Side.
=> Side = 24÷4 = 6Cm.
◆ We also know that diagonals of rhombus bisects each other at right angles and are equal.
So, In triangle AOD;
By Pythagoras Theorem;
AO= 1/2 AC
AO =1/2 × 6
AO=3Cm.
Also we know that side is 6Cm;
AD^2= DO ^2 + AO^2.
=> (6)^2= DO^2+ (3)^2
=> 36 = DO ^2 + 9
=> DO^2= 25
=>DO=5Cm.
◆ Since we know that BD is another diagonal &. DO = 1/2 BD.
=> BD = 2×DO
=> BD = 2×5
=> BD = 10 Cm.
◆◆ So the other diagonal is 10 Cm◆◆
HOPE IT HELPS
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