the population of a town increased by 8% annually if the present population is 54000 what was it a year ago
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Answered by
6
x + x ×8/100=54000
108x/100 =54000
x= 54000 ×100÷ 108
=500×100
=50000
108x/100 =54000
x= 54000 ×100÷ 108
=500×100
=50000
alok461gamilcom:
wrong
Answered by
20
Let the last year population = x
Present year population = 54000
Increased percent = g = 8 %
Present population = last year population × ( 100 + g )/100
54000 = x × ( 100 + 8 ) / 100
54000 = x × ( 108 / 100 )
( 54000 × 100 ) / 108 = x
50000 = x
Therefore,
The last yeat population = x = 50000
I hope this helps you.
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Present year population = 54000
Increased percent = g = 8 %
Present population = last year population × ( 100 + g )/100
54000 = x × ( 100 + 8 ) / 100
54000 = x × ( 108 / 100 )
( 54000 × 100 ) / 108 = x
50000 = x
Therefore,
The last yeat population = x = 50000
I hope this helps you.
:)
plz.mark it as brainliest
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