Question

the perimeter of a rhombus is 20cm. One of the diagonal is 8cm. Find the area of rhombus and length of the other diagonal.

Answer 1

Perimeter of rhombus = 4 × side
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Perimeter of rhombus = 20 

4 × side = 20

side = 20/4

side = 5 cm
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Let the length of other diagonal be 2x,

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By Pythagoras theorem,

(8/2)^2 + (2x/2)^2 = 5^2

4^2 + x^2 = 25

16 + x^2 = 25

x^2 = 25 -16

x^2 = 9

x = √9
x= 3


length of other diagonal = 2x = 2 ×3 = 6cm
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Area of rhombus = $\frac{Product of diagonals}{2}$

Area of rhombus = $\frac{ 8 * 6}{2}$

Area of rhombus = 8 * 3 = 24cm^2 



i hope this will help you


-by ABHAY

Answer 2

area of rhombus =24CM2