Math, asked by tapasarapur5276, 9 months ago

The perimeter of a rhombus is 260cm and one of its diagonals is 66cm, find the area of the rhombus and its other diagonal

Answers

Answered by welltododevon
0

Answer:

area of the rhombus is 3696 sq cm

area of the rhombus is 3696 sq cmother diagonal is 112 cm

Step-by-step explanation:

perimeter of the rhombus is 260 cm

then sides of the perimeter is given by

perimeter = 4 sides

sides= 260/4= 65 cm

one of the diagonal is 66 cm

we can find the other diagonal using, right angled triangle, both diagonal meet at the centre, there it will 4 right angled triangle.

using one of the triangle, we can find the half of the other diagonal

side^2 = (1st diagonal/2)^2 + (2nd diagonal/2)^2

65^2 = (66/2)^2+x^2

x^2=4225-1089

X=56 cm

it is half of the diagonal, length of the diagonal is 112cm

area of the rhombus using diagonals is

a=pq/2

a=66*112/2

a=3696 sq cm

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