The perimeter of a rhombus is 40 cm and the length of one of the diagonals is 16 cm. Find the length of the other diagonal and area of the rhombus. Please answer as fast as you can.
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Step-by-step explanation:
(i)Perimeter of rhombus=40cm
Side=1/4×40=40cm
One diogonal=16cm
Diogonals of rhombus bisect each other at right angles.
OB=√AB^2-OA^2
=√(10)^2-(8)^2
=√100-64
=√36
=6cm
diagonal BD=6×2=12cm
(ii)Area of rhombus
=1/2×product of diagonals
=1/2×12×16
=96cm^2
(i)12cm (ii)96cm^2
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