Question

the perimeter of a rhombus is 40 cm if the length of one of its diagonal is 12 cm what is the area​

Answer 1

Step-by-step explanation:

We Know that all the side of the rhombus are equal

Given:

So the peimeter of the rhombus is 40 cm so it's side will be 10cm

one digonal is 12 cm

drawing both the digonal and applying the fourmulae of the right angle triangle

that:

height² + base² =hypotenuse²

To find another digonal

one side that is base is 10 cm

height is 14 cm

hypotenuse is 16 cm

area =½ digonal 1 *digonal 2

$(1 \div 2) \times 16 \times 12 \\ 96$