Question

The perimeter of a rhombus is 4m. One of its diagonal is 4/3rd of the other.
Find the area of the rhombus.​

Answer 1

Step-by-step explanation:

Perimeter of rhombus=100 cm

∴one side of rhombus=

4

100

=25cm

Since diagonal of a rhombus bisect each other at right angle

∴AO=

2

1

×14=7cm.and∠AOB=90

∘

In ΔAOB

OB=

AB

2

−AO

2

OB=

25

2

−7

2

OB=

625−49

OB=

576

OB=24cm

∴ Length of other diagonal=2×OB=2×24=48cm

Area of the rhombus =

2

1

×product of diagonal

⇒

2

1

×48×14=336sq.cm

solution