the perimeter of a rhombus is 52 centimetre is a diagonal is 24 cm find the length of a diagonal its area
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4*side = 52
→ side = 52/4 = 13
by Pythagoras theorem ,
(1/2 of first diagonal)² + (1/2 of 2nd diagonal) ² = side²
→ (1/2 * 24)² + (1/2 of 2nd)² = 13²
→ 1/2 of 2nd = 5
→ 2nd = 10
second diagonal is of 10cm
area of Rhombus=diagonals/2
area of Rhombus=24*10/2
area of Rhombus =120cm²
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