The perimeter of a right angle triangle is 144 cm and its hypotenuse side is 65 cm. So, find the other 2 sides of triangle.
Is there anyone who can me to solve this question ??
Answers
Answer:
63 cm and 16 cm
Step-by-step explanation:
Given :
Perimeter of the right angled triangle = 144 cm .
Hypotenuse is given 65 cm .
Let the sides be x , y and z .
x = height .
y = base .
z = hypotenuse.
By Pythagoras theorem :
z² = y² + x²
⇒ ( 65 )² = y² + x²
⇒ 4225 = y² + x²
⇒ x² + y² = 4225 ..........( 1 )
Now perimeter = 144 cm
⇒ x + y + z = 144
⇒ x + y + 65 = 144
⇒ x + y = 144 - 65
⇒ x + y = 79
⇒ x = 79 - y .,................( 2 )
Put this equation 1 :
( 79 - y )² + y² = 4225
Use ( a - b )² = a² + b² - 2 ab
⇒ 79² + y² - 158 y + y² = 4225
⇒ 6241 + 2 y² - 158 y - 4225 = 0
⇒ 2016 + 2 y² - 158 y = 0
⇒ 2 y² - 158 y + 2016 = 0
⇒ y² - 79 y + 1008 = 0
⇒ y² - 63 y - 16 y + 1008 = 0
⇒ y ( y - 63 ) - 16 ( y - 63 ) = 0
⇒ ( y - 63 )( y - 16 ) = 0
By zero product rule :
either y = 63
or y = 16
x + y = 79.
So x = 63 or 16 .
ANSWER:
The two sides are 63 and 16 cm
16,63
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