The perimeter of a right angle triangle is 24cm. Hipotenus is 10 find the area of a triangle
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Area= 24cm^2
Perimeter and Hypotenuse was given so we can find the sum of Perpendicular and Base.
Now by Pythagoras Theorem and The alzebric Identity (a+b)^2 we can find the Product of Perpendicular and Base.
Area is 1/2x Perpendicular x Base
So it can be solved easily as shown below
Perimeter and Hypotenuse was given so we can find the sum of Perpendicular and Base.
Now by Pythagoras Theorem and The alzebric Identity (a+b)^2 we can find the Product of Perpendicular and Base.
Area is 1/2x Perpendicular x Base
So it can be solved easily as shown below
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jaiho20:
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