Question

The perimeter of a right angled triangle is 450 m. If its sides are in the ratio 5 : 12 : 13, then the area
of the triangle is
(1) 9000 m2
(2) 8765 m2
(3) 6750 m2
(4) 11750 m2

17
20

57. If 2 3 sin x sin x sin x 1 then 642 cos x 4 cos x 8cos x is equal to
(1) 3 (2) 4 (3) 2 (4) 1

Answer 1

Answer:

ans ...(3) 6750 m^2

Step-by-step explanation:

first you need to find out all the sides by taking the ratio as " x "....

As, 5x + 12x + 13x =450 ( perimeter)...

then height will be equal to 15

after that you can easily find out the area by using heron's formula...

Answer 2

Answer:

The perimeter of a right angled triangle is 450 m. If its sides are in the ratio 5 : 12 : 13, then the area of the triangle is 6750 $m^{2}$.

Step-by-step explanation:

• The perimeter of a right angled triangle is 450 m.

• its sides are in the ratio 5 : 12 : 13

• Let x be the common factor of the given ratio.

• So, the sides are 5x, 12x, 13x.

• Now, Perimeter of the triangle = Sum of all sides of that triangle

so, 5x+12x+13x = 450

⇒ 30x   =   450

⇒  x = 450/30

⇒  x = 15

• hence, the three sides of that triangle are : 5x=75m, 12x = 180m,13x = 195m.

• Area of a triangle= √[s(s-a)(s-b)(s-c)]

• where, s is the semi-perimeter of the triangle, i.e., s = 450/2 = 225m.

Hence, Area of the given triangle = $\sqrt{225(225-75)(225-180)(225-195)}$

                                                       = $\sqrt{225*150*45*30 }$

                                                       = 6750 sq.m.

If  sides of the triangles are in the ratio 5 : 12 : 13, then the area

of the triangle is 6750 $m^{2}$.