the perimeter of a right triangle is 40cm and its hypotenuse measures 17cm. find the area of the triangle
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C = 17
A + B + C = 40
A^2 + B^2 = C^2
A + B = 23
A^2 + B^2 = 289
B = 23 - A
A^2 + (23 - A)^2 = 289
A^2 + 529 - 46A + A^2 = 289
2A^2 - 46A + 240 = 0
A + B + C = 40
A^2 + B^2 = C^2
A + B = 23
A^2 + B^2 = 289
B = 23 - A
A^2 + (23 - A)^2 = 289
A^2 + 529 - 46A + A^2 = 289
2A^2 - 46A + 240 = 0
Rittick1:
the correct answer is 60
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