Question

The perimeter of a right triangle is 550 m. If its sides are in the ratio 12 : 11 : 7. What is the area of this triangle?

Answer 1

Perimeter of triangle a+b+c

Let a be 12x

Let b be 11x

Let c be 7x

Now, Perimeter Given is 550m

A.T.Q

12x+11x+7x=550

30x=550

x= 550/30

x=18.33

A=219.96

B=201.63

C=58.31

Step-by-step explanation:

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Answer 2

Answer:

12940.16

Step-by-step explanation:

P=a+b+c

12x+11x+7x=550

30x=550

x=55/3

Sides:

12x=12*55/3=220- greatest one is hypotenuse

11x=11*55/3=201.67- adjacent side to right angle

7x=7*55/3=128.33- adjacent side to right angle

Area of triangle: b*c/2 =

=201.67*128.33/2=12940.16