Question

the perimeter of a room is 92 1/2 m. if its breadth is 20 2/3 m, what is its length?​

Answer 1

Answer

perimeter= 2(l+b)

92 1/2 m = 2( l+ 20 2/3 )

185/2 m = 2( l+ 62/3 )

185/2 m = 2l + 2*62/3

185/2 m = 2l + 124/3

185/2 m - 124/3 m = 2l

by taking LCM we have to subtract it

555/6 - 248/6 = 2l

307/6 = 2l

307 / 2 = l

6

307 = l

12

25 7/12 = l