Question

The perimeter of a school volleyball court is 177 ft and the length is twice the width. What are the dimensions of the volleyball court

Answer 1

let width =b
length=2b
now,
perimeter=2(b+2b)
6b=177
b=29.5
width=29.5 ft
length=59 ft

Answer 2

Answer:

width = x = 29.5 ft

length = 2x = 59 ft

Given:

perimeter = 177 ft

length is twice the width.

To find:

The dimensions of the volleyball court.

Step-by-step explanation:

Hints-

perimeter of rectangle:

It is the sum of sides of rectangle.

let the width of the court be x ft.

it is given that, length is twice the width.

so, length = 2x ft.

perimeter of court = l + l + b + b

perimeter of court = 2l + 2b

perimeter of court = 2(l + b)

perimeter of court =  2(l + b)

put l = 2x, b = x

perimeter of court = 2(2x + x)

⇒ perimeter of court =  2(3x)

⇒ perimeter of court =  6x

perimeter is 177

⇒ 6x = 177

⇒ x = 177/6

⇒ x = 29.5

hence, dimension of volley court are

width = x = 29.5 ft

length = 2x = 59 ft

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