The perimeter of a semicircular protractor is 108 cm . find diameter of protractor.
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Let radius of the semicircle = r cm
Perimeter of the
semicircle = 2r + pi × r
= ( 2 + pi )r
= ( 2 + 22/ 7 ) r
= [( 14 + 22 ) / 7 ] r
P = 36r / 7 -----( 1 )
According to the problem given ,
P = 108 cm -----------( 2 )
( 1 ) = ( 2 )
36r/ 7 = 108
r = ( 108 × 7 ) / 36
r = 3 × 7
r = 21 cm
Therefore ,
Diameter of the semicircle = 2r
d = 2 × 21
d = 42 cm
Let radius of the semicircle = r cm
Perimeter of the
semicircle = 2r + pi × r
= ( 2 + pi )r
= ( 2 + 22/ 7 ) r
= [( 14 + 22 ) / 7 ] r
P = 36r / 7 -----( 1 )
According to the problem given ,
P = 108 cm -----------( 2 )
( 1 ) = ( 2 )
36r/ 7 = 108
r = ( 108 × 7 ) / 36
r = 3 × 7
r = 21 cm
Therefore ,
Diameter of the semicircle = 2r
d = 2 × 21
d = 42 cm
Rk2662:
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