Question

The perimeter of a sheet of tin in the shape of a quadrant of a circle is 12.5 cm. Find its area.
(Taken π = 22/7)

Answer 1

Area = 7.07 sq. cm.

Explanation:

Given:

The perimeter of a sheet of tin in the shape of a quadrant of a circle is 12.5 cm.

π = 22/7

A quadrant is a quarter of a circle.

Perimeter of a quadrant will be = (1/4 * perimeter of the circle)+ (2 * radius)

(1 / 4 * 2πr ) + 2r = (1 / 2 * 22 / 7 * r) + 2 r

(44 / 7 * r ) + 2 r = 12.5

r (44 / 7 + 2) = 12.5

r (44 / 7 + 14 / 7) = 12. 5

r ( 58/ 7 ) = 12.5

r = 12.5 * 7 / 58

 = 1.508 cm

Radius of the circle = 1.5 cm (approx)

Area of the circle = π r^2 = 22/ 7 * 1.5 * 1.5 = 7.07 sq. cm.