the perimeter of a square and a regular hexagon are equal .find the ratio of the area of the hexagon to the area of the square
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Side of the square = x units and side of regular hexagon = y units.
∴ 4x = 6y => x = 3/2 y
Area of square = 9/4y^2
Area of hexagon = 3√3/2×y^2
∴ Required ratio
= 3√3/2×y^2 : 9/4y^2 = 2√3: 3
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