the perimeter of a square are 40 and 96 respectively find the perimeter of another square equal in area to the sum of the first two square
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perimeter of square =4a
A.T.Q
4a=40
a=10 side of ist square (a)
similarly ; side second square =24(L)
A.T.Q---
Sum of area of squre =area of third square
a*a + l*l = z*z
10*10 +24*24= z*z
100+576= z*z
676 =z*z
26*26=z*z
Then ; z=26
perimeter of third square =26*4
104 sq unit
step-by-step explanation:
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