Math, asked by ashish837, 1 day ago

The perimeter of a square is increased by 25%. Find the percentage of increase in its area.

with correct explanation?​

Answers

Answered by suhrids88
0

Answer:

Let the side be 10 cm. Then the area will be

100

c

m

2

New side

=

125

%

o

f

10

=

12.5

c

m

;

A

r

e

a

=

(

12.5

)

2

=

156.25

Percentage increase in area

=

56.25

%

.

Alternatively: If x is the percentage increase in the side of a square, then increase in area is given by

x

+

x

+

x

×

x

100

=

2

x

+

x

2

100

=

25

+

25

+

25

×

25

100

=

56.25

%

Step-by-step explanation:

plz mark brainliest

Answered by ArockiaInfantRohith
1

Answer:

56.25%

Step-by-step explanation:

Let each side of the square be a. Then, area = .a2

New side =125a/100=5a/4. New area = (5a/4)^2 = (25a^2/16)

Increase in area = 25a^2/16−a^2=9a^2/16

Increase% = [9a^2/16*1/a^2*100] % = 56.25%.

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