The perimeter of a traingular field 240dm if two of its side are 78dm and 50dm find the length of the perpendicular on the side of length 50dm from the opposite vertex?
Answers
Answer:
Perimeter of the triangle = 240 dm
Two sides (given) = 78 dm and 50 dm
Third side of the triangle = 240 - (78 + 50)
= 240 dm - 128 dm
= 112 dm
s = (a + b + c)/2
= (78 + 50 + 112)/2
= 240/2
s = 120 dm
Area of the triangle = √s(s - a)(s - b)(s - c)
⇒ √120 (120 - 50)(120 - 78)(120 - 112)
⇒ √120*70*42*8
⇒ √2822400
Area of the triangle = 1680 sq dm
Now,
Area of the triangle = 1/2*base*height
Height = 2*area/base
⇒ (2*1680)/50
⇒ 336/5
height = 67.2 dm
• Perimeter of triangle = 240 dm
• Two sides = 78dm and 50dm
• What's the length of perpendicular ?
Formula to be used :-
• Third side = perimeter -( sum of two sides)
• Area of triangle =√s(s-a)(s-b)(s-c)
•Area of triangle = 1/2 × Base ×Height
• s = (a + b + c)/2
We know that,
Perimeter of a triangle = Sum of all sides
Given that,
Two sides = 78dm and 50dm
Now, find the 3rd side of the triangle.
Third side = Perimeter -( Sum of two sides)
= 240 - (78+50)
=240 - 128
= 112 dm
________________________________________________
Now, find the area of given triangle.
We know,
s = (a + b + c)/2
Where,
a = 78
b = 50
c = 112
Put the given values in the formula
⟶ s = (78 + 50 +112)/2
⟶ s = 240/2
⟶ s = 120 dm
Again,
Area of triangle =√s(s-a)(s-b)(s-c)
⠀⠀ ⠀= √ 120(120-78)(120-50)(120-112)
⠀⠀⠀⠀⠀⠀= √120 ×42×70 ×8
⠀⠀⠀⠀⠀⠀= √5040 × 560
⠀⠀⠀⠀⠀ = 1680
Area of triangle = 1680 dm²
_______________________________________________
According to the question, we are asked to find the value of h( Height)
We know,
Area of triangle = 1/2 × Base ×Height ( h)
⠀⠀⠀⠀⠀⠀⟶ 1680 ×2 /50 = h
⠀⠀⠀⠀ ⠀⟶ 3360/50 = h
⠀⠀⠀⠀⠀⠀ ⟶ 336/5 = h
⠀⠀⠀⠀⠀⠀⟶ 67.2 = h
Hence , the height of the triangle = 67.2 dm