Question

the perimeter of a triangle formed by the points (0,0),(1,0),0,1)IS​

Answer 1

Let A(1,0), O(0,0), B(0,1)

OA = 1 , OB= 1

AB = √OA²+OB²

= √1+1

= √2

Therefore ,

Perimeter of the triangle

OAB = OA + AB + OB

= 1+√2+1

= 2+√2

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