The perimeter of a triangle is 120 m. The sides are in ratio 5:12:13. Find the longest side of the triangle
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Answered by
1
let the sides of the triangle be 5a, 12a, 13a.
therefore:
5a + 12a + 13a = 120
30a = 120
a = 120/ 30
a = 4
therefore the longest side of the triangle = 13 x 4 = 52m
Answered by
0
The total parts are5 plus 12 plus 13 =30
The required length is 13×120/30=52
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