The perimeter of a triangle is 150 m and the product of differences (in m) of semi-perimeter and its respective sides is 496800. Find the area of the triangle
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Solution:-
Let the sides of the triangle be a, b and c
Given (s-a)*(s-b)*(s-c) = 496800
Semi-perimeter of the triangle = 150/2
S = 75 m _____________
Area of the triangle =√s(s-a)(s-b)(s-c)
___________
= √75 × (496800)
________
=√37260000
Area of the triangle = 6104.09 square meter
or 6104 square meter (rounded off)
Let the sides of the triangle be a, b and c
Given (s-a)*(s-b)*(s-c) = 496800
Semi-perimeter of the triangle = 150/2
S = 75 m _____________
Area of the triangle =√s(s-a)(s-b)(s-c)
___________
= √75 × (496800)
________
=√37260000
Area of the triangle = 6104.09 square meter
or 6104 square meter (rounded off)
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