The perimeter of a triangle is 276 m and the product of differences of semi-perimeter and its respective sides is 496800.Find the area of the triangle.
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Answered by
21
Given (p-a)(p-b)(p-c) = 496800, and 2p =276
Area of Triangle = sqrt[p(p-a)(p-b)(p-c)]
= sqrt[138*496800]
= 8280 cm^2
Area of Triangle = sqrt[p(p-a)(p-b)(p-c)]
= sqrt[138*496800]
= 8280 cm^2
Answered by
38
Answer:
Perimeter of triangle = 276 m
⇒ a+b+c = 276
⇒ Semi- Perimeter = a+b+c/2
= 276/2 = 138 m
Now,
(s-a) (s-b) (s-c) = 496800
Area of the triangle = √s (s-a) (s-b) (s-c)
= √138 x 496800
= 8680 cm²
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