the perimeter of a triangle is 288 m and the ratio of the sides is 3:4:5 find the area of triangle
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Answered by
27
3x+4x+5x= 288
12x=288
x=24
hence sides of triangle are
3*24,4*24,5*24
72,96,100
area = 1/2*base*height
=1/2 *72*96
= 3456sq unit
12x=288
x=24
hence sides of triangle are
3*24,4*24,5*24
72,96,100
area = 1/2*base*height
=1/2 *72*96
= 3456sq unit
abhi63715:
hi mamta
Answered by
13
let sides of the triangle are
3x ,4x, 5x
now , 3x+4x+5x = 288
x = 288/12
x = 24
3x = 72
4x = 96
5x = 120
area = √s(s-a)(s-b)(s-c)
= 3456 cm ² ams
3x ,4x, 5x
now , 3x+4x+5x = 288
x = 288/12
x = 24
3x = 72
4x = 96
5x = 120
area = √s(s-a)(s-b)(s-c)
= 3456 cm ² ams
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