there is a fraction whose denominator is 3 more than its numerator if the numerator is increased by 7 and the denominator is decreased by 2 the value of the fraction becomes 2. the fraction is
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Let the fraction be P/ 3
now, (P+7)/3_2=2
( P+7) =1×2
P=2_7
P=_5
hence the fraction is _5/3
now, (P+7)/3_2=2
( P+7) =1×2
P=2_7
P=_5
hence the fraction is _5/3
loneaamir1431:
soorry this is not option as given
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let the first fraction be x/x+3
x+7
------- = 2
x+3-2
x+7/x+1=2
x + 7= 2x +2
-x=-5
x=-5/-1=5
then the first fraction will be 5/8
x+7
------- = 2
x+3-2
x+7/x+1=2
x + 7= 2x +2
-x=-5
x=-5/-1=5
then the first fraction will be 5/8
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