The perimeter of a triangle is (3x^2+4x+2)cm.If two sides AB and BC are (5x+1)cm and (x^2-5x-4)cm,find CA i.e third side.
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Answer:
2x^2 + 4x + 5
Step-by-step explanation:
Let the length of third side be 'a'.
= > Perimeter = sum of all sides
= > 3x^2 + 4x + 2 = (5x + 1) + (x^2 - 5x - 4) + a
= > 3x^2 + 4x + 2 = 5x + 1 + x^2 - 5x - 4 + a
= > 3x^2 + 4x + 2 = x^2 - 3 + a
= > 3x^2 + 4x + 2 - x^2 + 3 = a
= > 2x^2 + 4x + 5 = a = third side
Length of third side is 2x^2 + 4x + 5.
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