Question

The perimeter of a triangle is 420 meter and its sides are in the ratio 6:7:8. find the area of the triangle.

Answer 1

6x +7x + 8x = 420
21x = 420
x= 20
6x = 120
7x = 140
8x = 160
area of triangle = √s(s-a)(s-b)(s-c)
s=420/2 = 210
√210(90)(70)(50)
=
$\sqrt{210 \times 90 \times 70 \times 50}$

Answer 2

p=a+b+c
let 6:7:8 be 6x,7x and 8x
420=6x+7x+8x
420=21x
420/21=x
20=x
so side of triangle are,6x=6×20=120cm
7x=7×20=140cm
8x=8×20=160cm
s=p/2=210cm
area of triangle=√s(s-a)(s-b)(s-c)
=√210(210-120)(210-140)(210-160)
=√210(90)(70)(50)
=√3×7×10×3×3×10×7×10×5×10

=3×7×10×10√5×3
=2100√15cm²
please select this as brain list answer