Question

The perimeter of a triangle is 45 cm. The longest side exceeds the shortest side by 8 cm and the sum
of the length of the longest and the shortest side is twice the length of the other side Find the lengths
of sides of the triangle.
The sum of three numbers is 20. If we multiply the first number by 2 and add the second numbert
in linked with determinants
​

Answer 1

Answer:

15cm

Step-by-step explanation:

Let the length of shortest side of the triangle is x cm, longest side be 8 cm + length of shortest side i.e. ( x + 8 ) cm

Shortest side = x cm

Longest side = ( x + 8 ) cm

Other or Remaining side = perimeter - length of shortest side - length if largest side

Remaining side = 45 - x - x - 8

Remaining side = ( 37 - 2x ) cm

Given in the question that the sum of length of the largest side and length of the shortest is equal to the 2 times if remaining side.

According to the question,

➡ Largest side + shortest side = 2 × remaining side

⏩ x + ( x + 8 ) = 2( 37 - 2x )

⏩ x + x + 8 = 74 - 4x

⏩ 2x + 8 = 74 - 4x

⏩ 2x + 4x = 74 - 8

⏩ 6x = 66

⏩ x = 11

Therefore,Therefore,

Smallest side = x cm = 1 1 cm

Largest side = ( x + 8 ) cm = ( 1 1 + 8 ) cm = 19 cm

Other side = ( 45 - 1 1 - 19 ) cm = ( 45 - 30 ) cm = 15 cm