Question

the perimeter of a triangle is 48 cm and its sides are 14 cm ,19 cm and (x+4)cm respectively .find the value of x

Answer 1

Answer:

PERIMETER OF TRIANGLE = A + B + C

SO , A = 14 , B= 19 , C= (X+4)

 PERIMETER = A+B+C

==> 48 = 14+19+(X+4)

==> 48 = 33 + X + 4

==> 48 = 37 + X

==> 48-37 = X

==> 11 = X

Answer 2

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