Math, asked by sm9410928, 7 months ago

the perimeter of a triangle is 4x + 5y - 6z. if two sides of a triangle are ( 2x + 3y - z ) and ( x + 3y - 2z ) respectively. find the third side of the triangle.​

Answers

Answered by sanjivdev
1

Answer:

x-y-3z

Step-by-step explanation:

Perimeter of triangle= A+B+C

4x+5y-6z=2x+3y-z+x+3y-2z+C

4x+5y-6z=3x+6y-3z+C

4x+5y-6z-3x-6y+3z=C

x-y-3z=C

C= x-y-3z

  • Hope this will helps you....
Answered by CHITRAKSHI110
3

Answer:

x - y - 3z

Step-by-step explanation:

It is given that

Sides of a triangle are 2x+3y- z and x + 3y - 2z

Let the third side be C

We know that

Perimeter = A+B+C (sum of sides of triangle)

4x + 5y - 6z = (2x + 3y - z) + (x + 3y - 2z) + C

4x + 5y - 6z = 2x + 3y - z + x + 3y - 2z + C

4x + 5y - 6z = 3x + 6y - 3z + C

C = 4x + 5y - 6z - 3x - 6y + 3z

C= x - y - 3z

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