The perimeter of a triangle is 5-3x+7y and two of its sides are 2y+3x-2 and 3y-x+3. Find the third side of the triangle.
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suppose 3rd side is Z
then, (2Y+ 3X-2) + (3Y-X+3) +Z = 5-3X+7Y
2Y+3X-2+3Y-X+3+Z=5-3X+7Y
2X+5Y+1+Z=5-3X+7Y
Z=4+2Y-5X ans
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