the perimeter of a triangle is 50cm. one side is 4cm longer than the smaller side and the third side is 6cm less than twice the smaller side. find the area of the triangle
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Answered by
133
Let the smaller side = x
then the sides will be = x , x+4 , 2x-6
perimeter = sum of the sides = x+x+4+2x-6 = 50
4x-2 = 50
4x = 52
x= 13
the sides are 13 , 17 , 20
then the sides will be = x , x+4 , 2x-6
perimeter = sum of the sides = x+x+4+2x-6 = 50
4x-2 = 50
4x = 52
x= 13
the sides are 13 , 17 , 20
Answered by
131
let the smaller side be x
1 side= x+4
3rd side=2x-6
perimeter=50 cm
x+x+4+2x-6=50
4x-2=50
4x=52
x=52/4
x=13
1 side=13+4=17 cm
2 side= 13cm
3rd side= 2*13-6=20 cm
now you can find the area...hope it helped
1 side= x+4
3rd side=2x-6
perimeter=50 cm
x+x+4+2x-6=50
4x-2=50
4x=52
x=52/4
x=13
1 side=13+4=17 cm
2 side= 13cm
3rd side= 2*13-6=20 cm
now you can find the area...hope it helped
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