the perimeter of a triangle is 65 meters.The second is 5 meters less than the first side .The third side is 7 meters more than the first side . what is the length of each side?
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heya
your solution is given below..
according to the question, the second side of the triangle is 5m less than the first side and the third side is 7m more than the first side.
let the first side be x.
therefore second side is x - 5 and third side is x + 7.
perimeter of the triangle is given = 65m
therefore sum of all sides = 65m
=> x + x - 5 + x + 7 = 65m
=> 3x + 2 = 65m
=> 3x = 65 - 2
=> 3x = 63
=> x = 63/3
=> x = 21m
hence, first side = x
= 21m
second side = x - 5
= 21 - 5
= 16m
third side = x + 7
= 21 + 7
= 28m
verification :-
perimeter of the triangle = sum of all sides
= 21 + 16 + 28
= 37 + 28
= 65
hence verified..
hope it will help u..
your solution is given below..
according to the question, the second side of the triangle is 5m less than the first side and the third side is 7m more than the first side.
let the first side be x.
therefore second side is x - 5 and third side is x + 7.
perimeter of the triangle is given = 65m
therefore sum of all sides = 65m
=> x + x - 5 + x + 7 = 65m
=> 3x + 2 = 65m
=> 3x = 65 - 2
=> 3x = 63
=> x = 63/3
=> x = 21m
hence, first side = x
= 21m
second side = x - 5
= 21 - 5
= 16m
third side = x + 7
= 21 + 7
= 28m
verification :-
perimeter of the triangle = sum of all sides
= 21 + 16 + 28
= 37 + 28
= 65
hence verified..
hope it will help u..
Answered by
0
Answer:
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Step-by-step explanation:
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