Question

The perimeter of a triangle is 8+13a+7a2 and two of its sides are 2a2+3a+2 and

3a2

-4a-1 . Find the third side.​

Answer 1

Answer:

perimeter of a triangle = 8+13a+7a2

first side =2a2+3a+2

second side = 3a2-4a-1

Therefore third side = 8+13a+7a2-( 2a2+3a+2+3a2-4a-1)

= 8+13a+7a2 - ( 5a2 - a -1 )

= 8 + 13a + 7a2 - 5a2 + a + 1

= 2a2 + 14 a + 9

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