Question

The pressure exerted by a liquid column of depth 0.5 m on the base of it's container is 5000Nm^2 .Find the density of the liquid.​

Answer 1

Answer:

Step-by-step explanation:

p = h ρ g

p = pressure in Pascals (Pa)

h = height of column in metres (m)

ρ  = density measured in kg per m^3

g = gravitation field strength in Newtons per kg (N/kg)

ρ = h p g

0.5m x 5000N/m^2 x 10N/kg

= 250,000 kg/m^3

Density is equal to 250,000 kg/m^3 which is ρ

Answer 2

Answer:

1000 kh m^3

Step-by-step explanation:

hope it helps!