The perimeter of a triangle is 90cm. The longest side exceeds the shortest by 16cm. The sum of the longest side and shortest side is twice the length of the other side. find the length of each side
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Answered by
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Answer:
the sides are 22, 30 and 38
Step-by-step explanation:
let longest side = a
shortest side = b
other side = c
given,
a = b + 16 ----(1)
a + b = 2c ----(2)
a + b + c = 90
=> 2c + c = 90 (from 2)
=> 3c = 90
=> c = 90/3 = 30
putting c in (2),
a + b= 2 × 30 = 60
=> b + 16 + b = 60
=> 2b = 60 - 16 = 44
=> b = 44/2 = 22
putting b in (1),
a = b + 16
=> a = 22+16 = 38
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