Question

the perimeter of a triangle measures 49 CM. the one side is 7 CM longer than the another and 5 CM shorter than the third. find the length of each side of a triangle

Answer 1

Let that one side be x
So second side will be x - 7
Third side will be x + 5

A/Q ->
x + x - 7 + x + 5 = 49
3x - 2 = 49
3x = 51
x = 17

The sides are ->
x = 17
x + 5 = 22
x - 7 = 10

Hope This Helps You!

Answer 2

Let the one side be x
Then the side which is five cm lesser than this is " x + 5 "
Anot side is " x - 7 "

[ x is 7 cm longer than (x-7) and x is 5cm shorter than (x+5)

Given, The perimeter of the triangle = 49 cm

x + x -7 + x + 5 =49

3x -2=49

3x = 51

x =17

Therefore, The three sides are 17,10,22 cm