Question

the perimeter of a triangular field is 240m its two sides are 78m and 50m, then area of triagular field is

Answer 1

Answer:

Step-by-step explanation:

Since the perimeter is 240 and the sides are 78 and 50.you have to find the third side.So in order to find it you reduce the sum of the other two sides from the perimeter

Assume third side as x

240-(78+50)=x

240-118=x

=112.

So the formulae is herons formulae.i.e

√120(120-112)(120-78)(120-50)

=

so the answer is 1680

Answer 2

Answer:

Perimeter = Sum of all sides

240= 78+50+third side

240=128+third side

third side=240-128=112

area= √s(s-a)(s-b)(s-c)

s=240/2 =120

area= √120 (120-112)(120-78)(120-50)

area=√120*8*42*70

√6*2*10*2*2*2*6*7*7*10

=6*2*2*10*7

=1680 cm²