the perimeter of a triangular field is 420 metre and its sides are in ratio 6:7:8. find the area of the triangular field
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let the side be 6x,7x,8x
perimeter = 420m
sum of sides = 420m
6x+7x+8x = 420m
21x =420m
x= 20m
hence the sides are
6x= 6×20 = 120 m
7x = 7×20= 140m
8x = 8×20= 160m
here we dont know what is the base and height so,
by using heron formula
s = half of perimeter = 420/2= 210m
area =√(s(s-a)(s-b)(s-c))
= √(210(210-120)(210-140)(210-160))
= √(210×90×70×50)
= √(10000×7×3×3×3×7×5)
= 100×21√15
= 2100√15 m²
NeelamG:
i hope it will help u
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