The perimeter of a triangular field is 540 and its sides are in the ratio 25:17:12. Find the area of the field. Also,find the cost of ploughing the field at ₹5 per m²
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given-
peri=540m
ratio of sides = 25:17:12
let the side be x
therefore, 25x + 17x + 12x=540m
=54x
therefore,x= 10m
the following sides are
250m , 170m, 120m
using herons formula
semiperimeter = a+b+c divided by 2
whole under root s*(s-a)(s-b)(s-c)
area= 90underroot 10
one meter sqaure = rupees 5
therefore 90 under root 10 = 90under root 10* 5
hence the cost is 450under root 10
bhavyachandrak:
i think the answer is this i am not sure
you can recheck it
Ok but thanks for answering :-)
your welcome
Let the sides of triangle 25x, 17x, 12x
Then perimeter= 540 = 25x+17x+12x = 54x
X= 10m
Then a= 250m, b = 170m, c= 120m
S = 540/2= 270m
Area = root under (270-250)*(270-120)*(270-170) = 100* root30
= 100*5.5 = 550m^2
Cost of ploughing 550*5 = ₹2750
Then perimeter= 540 = 25x+17x+12x = 54x
X= 10m
Then a= 250m, b = 170m, c= 120m
S = 540/2= 270m
Area = root under (270-250)*(270-120)*(270-170) = 100* root30
= 100*5.5 = 550m^2
Cost of ploughing 550*5 = ₹2750
area 550m^2 nd cost ₹2750
plzz confirm
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