Question

the perimeter of a triangular field is 540 m and its side are in the ratio 25:17:12 .find the area of a triangle also find the cost of ploughing the field at rupees 18.8o meter per square

Answer 1

let the sides be x

so;

s1=25x
s2=17x
s3=12x

now;
perimeter=s1+s2+s3
540=25x+17x12x
540=54x
x=10

s1=250
s2=170
s3=120

semi perimeter=(s1+s2+s3)/2
semi perimeter=a=27

by heron's formula

area=
$a(a - s1)(a - s2)(a - s3)$
area=90m2