The perimeter of a triangular field is 540m and its side are in ratio 25:17:12 .find the area of triangle
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let sides are in the ratio of 25x, 17x, 12x.
25x+ 17x+ 12x = 540
54x = 540
x =10
sides are 250m 170m and 120m.
25x+ 17x+ 12x = 540
54x = 540
x =10
sides are 250m 170m and 120m.
Answered by
5
Hello Rock
Your answer :-------
Let side of triangular field be 25X,17X and 12X
Perimeter of triangle = ( A+B+C)
A/Q
25X+17X+12X=540
=>54X=540
=>X=540/54
=>X=10
Hence,
25X=25×10=250n
17X=17×10=170m
12X=12×10=120m
If it helps you mark me as brainlist
Thanks
Your answer :-------
Let side of triangular field be 25X,17X and 12X
Perimeter of triangle = ( A+B+C)
A/Q
25X+17X+12X=540
=>54X=540
=>X=540/54
=>X=10
Hence,
25X=25×10=250n
17X=17×10=170m
12X=12×10=120m
If it helps you mark me as brainlist
Thanks
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