the perimeter of acertain parellogram is 28 if the four side of parellogram have equal length and if the height of the parellogram is 2 what is the area of the region enclosed by the parellogram?
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Answer:
14cm^2
Step-by-step explanation:
Perimeter =28 cm
As all 4 sides are equal so each side = 28÷4 = 7 cm
Height of Parallelogram = 2cm
Therefore, Area enclosed by Parallelogram = base×height
= (7× 2) cm^2
= 14 cm^2
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