The perimeter of an equilateral triangle is 42 cm. Find the perimeter of a square, each side of which is double the side of the triangle
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Answer:
Let the length of a side of the equilateral triangle and the square be l and L respectively.
Then, according to the given information, we have
Perimeter of equilateral triangle=42
⇒l+l+l=42
⇒3l=42
⇒l=14.
So, the length of a side of the square will be
L=2×l=2×14=28.
Therefore, the perimeter of the square is given by
Ps=4L=4×28=112
=4L=4×28=112.
Thus, the required perimeter of the square is 112 cm.
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Question : The perimeter of an equilateral triangle is 42 cm. Find the perimeter of a square. Each side of which is double the side of the triangle.
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Given :- The first, second and third class railway fares in the ratio between two stations are in the ratio as 6 : 4 : 1
the number of passenger of the three classes are 2 : 5 : 50.
To Find :- Total collection from each class.
Solution :-
Let first, second, third class fare, 6x,4x,x respectively.
Let number of the passenger of first, second, third be 2y,5y,50y respectively.
Total fare =
6x × 2y + 4x × 5y + x ×50y = 12xy + 20xy + 50xy
82xy = 12300 = xy=150
Total collection from 1st class = 12xy = 12 × 150 = 1800
2nd class = 20xy = 20 × 150 = 3000
3rd class = 50xy = 50 × 150 = 7500
Hence,Total collection from each class are ₹1800, ₹3000, ₹7500.
Hence the answer is ₹1800, ₹3000 and ₹7500.
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