Question

the perimeter of an isoceles is 24cm the length of an congruent side is 13cm less and twice the length of its base. find the length of all the sides of a triangle​

Answer 1

Answer:

Let the sides be x, y, z

Let the 2 congruent sides be x and z

According to above situation:-

x + y + z = 24cm....(1)

x =z = 2y- 13 cm....(2)

By substituting x=z in (1)

2z + y = 24cm

z=2y - 13cm

z -2y + 13=0....(3)

2z + y - 24= 0....(4)

BY USING ELIMINATION METHOD...

2z + y - 24=0 *(1)

z - 2y +13 =0 *(2)

2z+ y - 24=0

-(2z - 4y + 26=0)

2z + y - 24=0

-2z +4y -26 =0

= 0+5y-50=0

5y = 50

y= 50/5

y=10 cm...(5)

By substituting (5) in (3)

z -2y + 13 =0

z-20 +13 =0

z - 7 =0

z= 7cm

AS x = z

x = z =7 cm

y= 10 cm

VERIFICATION :-

Substituting all the values in (1)

x + y + z =24

7 + 7 + 10 = 24

14 +10 = 24

24=24