Question

The perimeter of an isoceles triangle is 42cm. The base is 1 1/2 times the equal side .Fin the length of each side.​

Answer 1

Answer:

let yhe equal side be x

base be11x/2

a/q

x+x+11x/2=42

2x/2+2x/2+11x/2=42

15x/2=42

5x/2=14

5x=28

x=28/5 =5.6cm

equal side =5.6cm

base=11/2×5.6= 30.8 cm

add me as brainliest.

Answer 2

Given :

• The perimeter of an isoceles triangle is 42cm.
• The base is 11/2 times the equal side

To Find :

• Length of each equal side

Solution :

Let the equal sides of the isosceles triangle be x.

[Two sides are of equal length in an isosceles triangle]

We have been given that the third (base) is 11/2 times the equal side (x).

•°• Third side → 11x/2

Perimeter : Sum of all sides.

Perimeter of the given isosceles triangle is 42 cm.

$\longrightarrow$$\sf{\dfrac{11}{2}\:\times\:x\:+\:x\:+\:x=\:42}$

$\longrightarrow$ $\sf{\dfrac{11x}{2}\:+\:2x=42}$

$\longrightarrow$ $\sf{\dfrac{11x+4x}{2}\:=42}$

$\longrightarrow$ $\sf{\dfrac{15x}{2}=42}$

$\longrightarrow$ $\sf{15x=42\:\times\:2}$

$\longrightarrow$ $\sf{15x=84}$

$\longrightarrow$ $\sf{x=\dfrac{84}{15}}$

$\longrightarrow$ $\sf{x=5.6}$

Length of equal sides of the isosceles triangle is 5.6 cm.

The base is 11/2 of the equal side, i. e 5.6 cm.

$\longrightarrow$ $\sf{Third\:side\:=\:\dfrac{11\:\times\:x}{2}}$

$\longrightarrow$ $\sf{Third\:side\:=\:\dfrac{61.6}{2}}$

$\longrightarrow$ $\sf{Third\:side\:=\:30.6\:}$

Sides of the isosceles triangle :

$\large{\boxed{\sf{\purple{First\:\:two\:equal\:side=\:x\:=\:5.6\:cm}}}}$

$\large{\boxed{\sf{\purple{Third\:side\:=\:30.6\:cm}}}}$